Physics - Heat & Thermo Question with Solution | TestHub

$\begin{array}{rl}& \Delta \mathrm{U}=0(\text{ Cyclic process })\\ & \Delta \mathrm{Q}=\mathrm{W}=\text{ area of }\mathrm{P}-\mathrm{V}\text{ curve. }\\ & =\pi \times \left(140\times 10^3\mathrm{Pa}\right)\times \left(140\times 10^{-6}{\mathrm{m}}^3\right)\\ & \Delta \mathrm{Q}=61.6\mathrm{J}\end{array}$