A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature ( 2 7 ∘ C ) . The ratio of specific heat of gases at constant volume respectively is:

( C v ) dia ( C v ) mono = 2 5 R 2 3 R = 5 3

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PhysicsHeat & ThermoKTGEasy2 minPYQ_2024

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A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature $(2 7^{\circ} C)$ . The ratio of specific heat of gases at constant volume respectively is:

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Answer:

Solution:

$\frac{( C _{v} ) _{mono}}{( C _{v} ) _{dia}} = \frac{\frac{3}{2} R}{\frac{5}{2} R} = \frac{3}{5}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2024

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