Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesMedium2 minPYQ_2023
PhysicsMediumsingle choice

Heat energy of735 Jis given to a diatomic gas allowing the gas to expand at constant pressure. Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal energy of the gas will be:

Options:

Answer:
A
Solution:

For isobaric process and diatomic gas we can write, ΔQ=nCPΔT=735 J

 n7R2ΔT=735 JnRΔT=210

Now internal energy will be,

ΔU=nCVΔT=n5R2ΔT=52×210

=525 J

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes
2mℹ️ Source: PYQ_2023

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