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PhysicsHeat & ThermoKTGEasy2 minPYQ_2023
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The temperature of an ideal gas is increased from 200 K to 800 K. If r.m.s. speed of gas at 200 K is v0. Then, r.m.s. speed of the gas at 800 K will be:

Options:

Answer:
D
Solution:

At 200 K, the rms speed is given by

v0=3R×200M   ...(1)

At 800 K, the rms speed is given by

v'=3R×800M   ...2

Divide equation (2) by equation (1) and solve to calculate the required speed.

v'v0=3R×800M3R×200M=800200= 2v'=2v0

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG
2mℹ️ Source: PYQ_2023

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