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PhysicsHeat & ThermoDifferent processesMedium2 minPYQ_2023
PhysicsMediumsingle choice

A sample of gas at temperatureTis adiabatically expanded to double its volume. The work done by the gas in the process is given, (givenγ=32) :

Options:

Answer:
D
Solution:

Work done by gas in adiabatic process is:

W=-P2V2-P1V1γ-1

  =-nRT2-T1γ-1

 For an adiabatic process, T1V1γ-1=T2V2γ-1

TV32-1=T22V32-1TV12=T22V12T2=T2

Now, work done is W=RT1-T2γ-1=RT-T212=RT2-2

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes
2mℹ️ Source: PYQ_2023

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