Given below are two statements: Statement I : The temperature of a gas is - 73 ° C . When the gas is heated to 527 ° C , the root mean square speed of the molecules is doubled. Statement II : The prod

Question

Given below are two statements: Statement I : The temperature of a gas is - 73 ° C . When the gas is heated to 527 ° C , the root mean square speed of the molecules is doubled. Statement II : The product of pressure and volume of an ideal gas will be equal to translational kinetic energy of the molecules. In the light of the above statements, choose the correct answer from the options given below:

TestHub · Accepted Answer

Given: T 1 = - 73 ° C = - 73 + 273 K = 200 K and T 2 = 527 ° C = 527 + 273 K = 800 K Therefore, V r m s , 1 V r m s , 2 = 3 R T 1 M 3 R T 2 M = T 1 T 2 = 200 800 = 1 2 V r m s , 2 = 2 V r m s , 1 Hence, Statement-I is true. Now, P V = n R T But translational KE = 3 2 nRT Hence, Statement-II is false.

Physics - Heat & Thermo Question with Solution | TestHub

Options:

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