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PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2022
PhysicsEasysingle choice

A certain amount of gas of volumeVat27°Ctemperature and pressure2×107N m-2expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Useγ=1.5)

Options:

Answer:
B
Solution:

Given here, P1=2×107 N m-2=2×107 Pa

Using Boyle's law,

P1V1=P2V2

Since V2=2V1.

Hence, P2=P12 (isothermal expansion)

P2=1×107 Pa

Now, during adiabatic expansion, 

P2V2γ=P32V2γ

P3=1×10721.5=3.536×106 Pa

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes
2mℹ️ Source: PYQ_2022

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