Statement - I : When μ amount of an ideal gas undergoes adiabatic change from state P 1 , V 1 , T 1 to state P 2 , V 2 , T 2 , then work done is W = μ R T 2 - T 1 1 - γ , where γ = C P C V and R = uni

Question

Statement - I : When μ amount of an ideal gas undergoes adiabatic change from state P 1 , V 1 , T 1 to state P 2 , V 2 , T 2 , then work done is W = μ R T 2 - T 1 1 - γ , where γ = C P C V and R = universal gas constant. Statement - II : In the above case, when work is done on the gas, the temperature of the gas would rise.

TestHub · Accepted Answer

The work done in an adiabatic process is given by,

$W_{adiabatic} = \frac{n R (T_{f} - T_{i})}{1 - γ} \to$ statement I is true.

For adiabatic process $∆ Q = 0$ . From the first law of thermodynamics,

$∆ Q = W + Δ U$

$0 = W + Δ U$

$Δ U = - W$

If work is done on the gas, i.e. work is negative

$∴ Δ U$ is positive.

$∴$ The temperature will increase. Hence, statement II is also true.

Physics - Heat & Thermo Question with Solution | TestHub

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