Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGHard2 minPYQ_2021

PhysicsHardsingle choice

Two spherical soap bubbles of radii $r_{1}$ and $r_{2}$ in vacuum combine under isothermal conditions. The resulting bubble has a radius equal to:

Answer:

Solution:

Number of moles is conserved.

$n_{1} + n_{2} = n_{3}$

$P_{1} V_{1} + P_{2} V_{2} = P_{3} V$

$\frac{4 S}{r_{1}} (\frac{4}{3} π r_{1}^{3}) + \frac{4 S}{r_{2}} (\frac{4}{3} π r_{2}^{3}) = \frac{4 S}{r_{3}} (\frac{4}{3} π r_{3}^{3})$

$r_{1}^{2} + r_{2}^{2} = r_{3}^{2}$

$r_{3} = \sqrt{r_{1}^{2} + r_{2}^{2}}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2021

Loading discussions...