When the temperature of a metal wire is increased from 0 º C to 10 º C , its length increases by 0 . 02 % .The percentage change in its mass density will be closed to:

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Δ ℓ = ℓ α Δ t α = Δ ℓ ℓ Δ T = 0 . 02 100 × 10 ; α = 2 × 10 - 5 γ = 3 α = 6 × 10 - 5 Δ V V = γ × Δ T ; Δ V V × 100 = 6 × 10 - 5 × 10 × 100 = 6 × 10 - 2 Volume increase by 0 . 06 % therefore density decrease by 0 . 06 %

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