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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2020

PhysicsEasysingle choice

A cyclic process for $1 mol$ of an ideal gas is shown in the $V - T$ diagram. The work done in $AB, BC$ and $CA$ respectively are

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Answer:

Solution:

During AB process is isochoric.

$∴ Δ V = 0 ∴ W = 0$

During $BC$ , the process is isothermal.

$∴ Δ T = 0$

$∴ W = {RT}_{2} ln \frac{V_{2}}{V_{1}}$

During $CA$ , the process is isobaric. So, the pressure is constant.

$∴ W = P (V_{1} - V_{2})$

But $P V_{1} = R T_{1}$

$∴ P = \frac{{RT}_{1}}{V_{1}} = \frac{{RT}_{2}}{V_{2}} ∴ W = \frac{{RT}_{1}}{V_{1}} (V_{1} - V_{2}) = \frac{{RT}_{2}}{V_{2}} (V_{1} - V_{2})$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: PYQ_2020

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