Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2019

PhysicsEasysingle choice

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume for this process is $TV^{x} =$ constant, then $x$ is:

Options:

Answer:

Solution:

Equation of adiabatic change is $TV^{γ - 1} = constant$ Put $γ = \frac{7}{5}$ , we get: $γ - 1 = \frac{7}{5} - 1$ $∴ x = \frac{2}{5}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: PYQ_2019

Doubts & Discussion

Loading discussions...