Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoSecond Law of ThermodynamicsEasy2 minPYQ_2018

PhysicsEasysingle choice

The efficiency of an ideal heat engine working between the freezing point and boiling point of water, isNEET 2018

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Answer:

Solution:

efficiency of ideal heat engine, $η = 1 - \frac{T_{2}}{T_{1}}$

$T_{2} :$ temperature of sink

$T_{1} :$ temperature of source

$Efficiency in Percentage, η = \frac{T_{1} - T_{2}}{T_{1}} \times 100$

$T_{1} = 373, T_{2} = 273$

$η = \frac{100}{373} \times 100 = 26.8 %$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Second Law of Thermodynamics

⏱ 2mℹ️ Source: PYQ_2018

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