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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesMedium2 minPYQ_2018

PhysicsMediumsingle choice

The Volume $(V)$ of a monoatomic gas varies with its temperature $(T)$ , as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state $A$ to state $B$ , is

NEET 2018

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Answer:

Solution:

$V \propto T$

$\Rightarrow$ Isobaric process

$W = P ∆ V = n R ∆ T$

$∆ Q = n C_{P} ∆ T$

For mono atomic gas $f = 3$

$C_{P} = (\frac{f}{2} R + R) = \frac{5}{2} R$

So $\frac{W}{∆ Q} = \frac{n R ∆ T}{n C_{P} ∆ T} = \frac{2}{5}$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: PYQ_2018

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