A mass of 50 g of water in a closed vessel, with surroundings at a constant temperature takes 2 minutes to cool from 3 0 ∘ C to 2 5 ∘ C . A mass of 100 g of another liquid in an identical vessel with

Question

A mass of 50 g of water in a closed vessel, with surroundings at a constant temperature takes 2 minutes to cool from 3 0 ∘ C to 2 5 ∘ C . A mass of 100 g of another liquid in an identical vessel with identical surroundings takes the same time to cool from 3 0 ∘ C to 2 5 ∘ C . The specific heat of the liquid is : (The water equivalent of the vessel is 30 g .)

TestHub · Accepted Answer

As the surrounding is identical, vessel is identical time taken to cool both water and liquid (from 3 0 ∘ C to 2 5 ∘ C ) is same 2 minutes, therefore ( dt dQ ​ ) water ​ = ( dt dQ ​ ) liquid ​ or, t ( m W ​ C W ​ + W ) Δ T ​ = t ( m ℓ ​ C ℓ ​ + W ) Δ T ​ ( W = water equivalent of the vessel ) or, m w ​ C w ​ = m ℓ ​ C ℓ ​ ∴ Specific heat of liquid, C ℓ ​ = m ℓ ​ m W ​ C W ​ ​ = 100 50 × 1 ​ = 0.5 kcal / kg

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