500 g of water and 100 g of ice at 0 ∘ C are in a calorimeter whose water equivalent is 40 g .10 g of steam at 10 0 ∘ C is added to it. Then water in the calorimeter is : (Latent heat of ice = 80 cal

Question

500 g of water and 100 g of ice at 0 ∘ C are in a calorimeter whose water equivalent is 40 g .10 g of steam at 10 0 ∘ C is added to it. Then water in the calorimeter is : (Latent heat of ice = 80 cal / g , Latent heat of steam = 540 cal / g )

TestHub · Accepted Answer

As 1 g of steam at 10 0 ∘ C melts 8 g of ice at 0 ∘ C . 10 g of steam will melt 8 × 10 g of ice at 0 ∘ C Water in calorimeter = 500 + 80 + 10 g = 590 g

Physics - Heat & Thermo Question with Solution | TestHub

Options:

Doubts & Discussion