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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2012

PhysicsEasysingle choice

A thermodynamic system is taken through the cycle $A BC D$ as shown in figure. Heat rejected by the gas during the cycle is
NEET 2012 (Screening)

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Answer:

Solution:

For given cyclic process, $Δ U = 0$ $∴ Q = W$ Also, $W = -$ area enclosed by the curve $= A B \times A D = (2 p - p) (3 V - V) = - p \times 2 V$ $∴$ Heat rejected $= 2 p_{V}$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: PYQ_2012

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