A black body at 22 7 ∘ C radiates heat at the rate of 7 cal cm − 2 s − 1 . At a temperature of 72 7 ∘ C , the rate of heat radiated in the same units will beNEET 2009 (Screening)

Key Idea Apply Stefan's law of radiation. E E 2 E 1 ⇒ E 2 = σ T 4 = [ T 2 T 1 ] 4 = 7 [ 273 + 227 273 + 727 ] 4 = ( 500 1000 ) 4 × 7 = 112 cal − cm − 2 s − 1

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoRadiationEasy2 minPYQ_2009

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A black body at $22 7^{\circ} C$ radiates heat at the rate of $7 cal cm^{- 2} s^{- 1}$ . At a temperature of $72 7^{\circ} C$ , the rate of heat radiated in the same units will beNEET 2009 (Screening)

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Key Idea Apply Stefan's law of radiation. $E \frac{E _{1}}{E _{2}} \Rightarrow E_{2} = σ T^{4} = [\frac{T _{1}}{T _{2}}]^{4} = 7 [\frac{273 + 727}{273 + 227}]^{4} = (\frac{1000}{500})^{4} \times 7 = 112 cal - cm^{- 2} s^{- 1}$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Radiation

⏱ 2mℹ️ Source: PYQ_2009

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