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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2008

PhysicsEasysingle choice

At $1 0^{\circ} C$ the value of the density of a fixed mass of an ideal gas divided by its pressure is $x$ . At $11 0^{\circ} C$ this ratio isNEET 2008 (Screening)

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Solution:

Let the ratio of density and pressure be r. From Ideal Gas Equation, $ρ = \frac{PM}{RT}$ $r = \frac{ρ}{P} = \frac{M}{RT} ∴ \frac{r _{2}}{r _{1}} = \frac{T _{1}}{T _{2}} = \frac{273 + 10}{273 + 110} = \frac{283}{383} r_{2} = \frac{283}{383} (as, r_{1} = x)$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: PYQ_2008

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