For a black body at temperature 72 7 ∘ C , its radiating power is 60 W and the temperature of surrounding is 22 7 ∘ C . If temperature of the black body is changed to 122 7 ∘ C , then its radiating power will be:NEET 2002

We can use the formula P ∝ ( T 4 − T 0 4 ) ∴ P 1 P 2 = ( 1000 ) 4 − ( 500 ) 4 ( 1500 ) 4 − ( 500 ) 4 = 50 0 4 ( 2 4 − 1 ) 50 0 4 ( 3 4 − 1 ) ∴ 60 P 2 = 15 80 ⇒ P 2 = 320 W

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoRadiationMedium2 minPYQ_2002

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For a black body at temperature $72 7^{\circ} C$ , its radiating power is $60 W$ and the temperature of surrounding is $22 7^{\circ} C$ . If temperature of the black body is changed to $122 7^{\circ} C$ , then its radiating power will be:NEET 2002

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Solution:

We can use the formula $P \propto (T_{4} - T_{0}^{4}) ∴ \frac{P _{2}}{P _{1}} = \frac{( 1500 ) ^{4} - ( 500 ) ^{4}}{( 1000 ) ^{4} - ( 500 ) ^{4}} = \frac{50 0 ^{4} ( 3 ^{4} - 1 )}{50 0 ^{4} ( 2 ^{4} - 1 )} ∴ \frac{P _{2}}{60} = \frac{80}{15} \Rightarrow P_{2} = 320 W$

Stream:NEETSubject:PhysicsTopic:Heat & ThermoSubtopic:Radiation

⏱ 2mℹ️ Source: PYQ_2002

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