Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationSatellite MotionMedium2 minQB

PhysicsMediumsingle choice

Periodic-time of satellite revolving around the earth is - ( $ρ$ is density of earth)

Answer:

Solution:

$\frac{GM m}{r ^{2}} = \frac{m v ^{2}}{r}$ $v = \frac{GM}{r ^{2}}$

$T = \frac{2 π r}{v} = \frac{2 π r ^{\frac{3}{2}}}{GM} = \frac{2 π r ^{\frac{3}{2}}}{G ρ \times \frac{4}{3} π r ^{3}}$ $T \propto \frac{1}{ρ}$

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Satellite Motion

⏱ 2mℹ️ Source: QB

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