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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceMedium2 minQB

PhysicsMediumnumerical

A particle of mass m is moving in circular motion of radius r with constant speed v in influence of two fixed particles of mass M. Plane of circular motion is perpendicular to line joining fixed particles as shown. Speed of particle is given as $v = \frac{GM}{nr}$ , find value of n ( $a = r 3$ )

Answer:

4.00

Solution:

Ans (4.00)

$2 F cos 6 0^{\circ} = 2 [\frac{GM m}{( 2 r ) ^{2}}] \cdot \frac{1}{2} = \frac{m v ^{2}}{r}$

$\Rightarrow V = \frac{GM}{4 r}$

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: QB

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