Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2024

PhysicsEasysingle choice

A body which is initially at rest at a height $R$ above the surface of the Earth of radius R, falls freely towards the Earth, then its velocity on reaching the surface of the Earth is

Options:

Answer:

Solution:

Increase in kinetic energy = Decrease in potential energy $∴ \frac{1}{2} m v^{2} = \frac{m g R}{1 + \frac{R}{R}} = \frac{m g R}{2} (Δ U = \frac{m g h}{1 + \frac{h}{R}}, h = R) \Rightarrow m v^{2} = m g R \Rightarrow v = g R$

Stream:BITSATSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2024

Doubts & Discussion

Loading discussions...