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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minPYQ_2023

PhysicsMediumsingle choice

For a satellite orbiting around the earth in a circular orbit, the ratio of potential energy to kinetic energy at same height is

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Answer:

Solution:

$∴ ∴ K.E = \frac{GM m}{2 r} P.E = - \frac{GM m}{r} \frac{K \cdot E}{∣ P . E} = \frac{GM m}{2 r} \times \frac{r}{GM m} \frac{P.E}{K.E} = \frac{2}{1} = 2$

Stream:MHT_CETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2023

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