A body weighs 300 N on the surface of the earth. How much will it weigh at a distance 2 R below the surface of earth? ( R → Radius of earth)

Acceleration due to gravity at depth d , g d = g ( 1 − R d ) = g ( 1 − 2 1 ) ∵ d = 2 R = 2 g ∴ Weight of the body at depth d 1 W d = mg d = 300 × 2 1 = 150 N

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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2023

PhysicsEasysingle choice

A body weighs $300 N$ on the surface of the earth. How much will it weigh at a distance $\frac{R}{2}$ below the surface of earth? ( $R \to$ Radius of earth)

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Solution:

Acceleration due to gravity at depth $d$ , $g_{d} = g (1 - \frac{d}{R}) = g (1 - \frac{1}{2}) ∵ d = \frac{R}{2} = \frac{g}{2}$ $∴$ Weight of the body at depth $d_{1}$ $W_{d} = mg_{d} = 300 \times \frac{1}{2} = 150 N$

Stream:MHT_CETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2023

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