The percentage decrease in the weight of a rocket, when taken to a height of $32 km$ above the surface of earth will, be
(Radius of earth $= 6400 km$ )

Question

The percentage decrease in the weight of a rocket, when taken to a height of 32 km above the surface of earth will, be (Radius of earth = 6400 km )

TestHub · Accepted Answer

Acceleration due to gravity at a height h < < R is g ' = g 1 - 2 h R Now, change in g is ∴ Δ g g = 2 h R Percentage change is ⇒ Δ g g × 100 = 2 h R × 100 = 2 × 32 6400 × 100 = 1 %

Physics - Gravitation Question with Solution | TestHub

Options:

Doubts & Discussion