When the value of acceleration due to gravity ' g ' become 3 g above surface of earth at height ' h ' then relation between ' h ' and ' R ' is ( R = radius of earth)

g ′ = g ( R + h ) 2 R 2 = 3 g 3 1 = ( R + h ) 2 R 2 3 1 = R + h R h = ( 3 − 1 ) R

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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2021

PhysicsEasysingle choice

When the value of acceleration due to gravity ' $g$ ' become $\frac{g}{3}$ above surface of earth at height ' $h$ ' then relation between ' $h$ ' and ' $R$ ' is $(R = radius of earth)$

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Solution:

$g^{'} = g \frac{R ^{2}}{( R + h ) ^{2}} = \frac{g}{3} \frac{1}{3} = \frac{R ^{2}}{( R + h ) ^{2}} \frac{1}{3} = \frac{R}{R + h} h = (3 - 1) R$

Stream:MHT_CETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2021

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