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PhysicsGravitationSatellite MotionEasy2 minPYQ_2021

PhysicsEasysingle choice

Two identical particles of mass $1 kg$ each go round a circle of radius $R$ , under the action of their mutual gravitational attraction. The angular speed of each particle is:

Question diagram: Two identical particles of mass 1 kg each go round a circle

Options:

Answer:

Solution:

$F = \frac{G m^{2}}{(2 R)^{2}} = m R ω^{2}$

$ω = \frac{1}{2} \sqrt{\frac{G}{R^{3}}}$

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Satellite Motion

⏱ 2mℹ️ Source: PYQ_2021

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