Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minPYQ_2021

PhysicsMediumsingle choice

A point particle is held on the axis of a ring of mass $m$ and radius $r$ at a distance $r$ from its centre C. When released, it reaches $C$ under the gravitational attraction of the ring. Its speed at $C$ will be

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Answer:

Solution:

Let ' $M$ ' be the mass of the particle Now, $E_{initial} = E_{final}$ i.e. $\frac{GMm}{2 r} + 0 = \frac{GM m}{r} + \frac{1}{2} MV^{2}$ or, $\frac{1}{2} MV^{2} = \frac{GM m}{r} [1 - \frac{1}{2}]$ $\Rightarrow \frac{1}{2} V^{2} = \frac{G m}{r} [1 - \frac{1}{2}]$ or, $V = \frac{2 Gm}{r} (1 - \frac{1}{2})$

Stream:BITSATSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2021

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