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PhysicsGravitationKepler's LawEasy2 minPYQ_2021

PhysicsEasysingle choice

The time period of a satellite in a circular orbit of the radius $R$ is $T .$ The period of another satellite in a circular orbit of the radius $9 R$ is:

Options:

Answer:

Solution:

$T^{2} \propto R^{3}$ .
${(\frac{T^{'}}{T})}^{2} = {(\frac{9 R}{R})}^{3}$
$T^{2} = T^{2} \times 9^{3}$
$T^{'} = T \times 3^{3}$
$T^{'} = 27 T$

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Kepler's Law

⏱ 2mℹ️ Source: PYQ_2021

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