A pendulum is oscillating with frequency ' n ' on the surface of the earth. It is taken to a depth 2 R below the surface of earth. New frequency of oscillation at depth 2 R is [ R is the

Question

A pendulum is oscillating with frequency ' n ' on the surface of the earth. It is taken to a depth 2 R ​ below the surface of earth. New frequency of oscillation at depth 2 R ​ is [ R is the radius of earth]

TestHub · Accepted Answer

Frequency of a simple pendulum is given by ​ n = 2 π 1 ​ ℓ g ​ ​ ∴ n n ′ ​ = g g ′ ​ ​ g ′ = g ( 1 − R d ​ ) = g ( 1 − 2 1 ​ ) = 2 g ​ ∴ n ′ = 2 ​ n ​ ​

Physics - Gravitation Question with Solution | TestHub

Options:

Doubts & Discussion