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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

The height above surface of earth where the value of gravitational acceleration is one fourth of that at surface, will be

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Answer:

Solution:

$g' = \frac{g R^{2}}{{(R + h)}^{2}}$

$\frac{g}{4} = \frac{g R^{2}}{{(R + h)}^{2}}$

$\frac{1}{4} = \frac{R^{2}}{{(R + h)}^{2}}$

${(R + h)}^{2} = 4 R^{2}$

$(R + h) = 2 R$

$h = R = R_{e}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2020

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