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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2020

PhysicsEasysingle choice

The escape velocity from the earth is about $11 k m s^{- 1}$ . The escape velocity from a planet having twice the radius and the same mean density as the earth is

Options:

Answer:

Solution:

The escape velocity can be given by

$v = \sqrt{\frac{2 G M}{R}} = \sqrt{2 G \frac{4}{3} π R^{2} d}$

$v \propto R \sqrt{d}$

Hence escape velocity from the other planet is,

$v' = 2 v_{0}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2020

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