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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

What should be the angular velocity of earth about its own axis so that the weight of the body at the equator would become $\frac{3}{4}$ th of its present value?

Options:

Answer:

Solution:

$Weight of body = \frac{3}{4}$ of present weight so

$g_{e f f} = \frac{3}{4} g$

at equator

$g_{e f f} = g - R ω^{2} = \frac{3}{4} g$

$ω = \sqrt{\frac{g}{4 R}} = \frac{1}{2} (\sqrt{\frac{g}{R}}) = \frac{1}{2} \times \frac{1}{800}$

$= \frac{1}{1600} r a d s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2020

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