Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2020

PhysicsEasysingle choice

Two particles of masses $m a n d 9 m$ are separated by a distance $r$ . At a point on the line joining them, the gravitational field is zero. The gravitation potential at that point is ( $G$ = Universal constant of gravitation)

Options:

Answer:

Solution:

For the system described above

$F = 0, \frac{G m}{r_{1}^{2}} = \frac{G (9 m)}{r_{2}^{2}} \Rightarrow \frac{r_{2}}{r_{1}} = 3$

$\begin{array}{l} r_{2} = \frac{3}{4} r and r_{1} = \frac{1}{4} r \\ V = - \frac{G m}{r_{1}} - \frac{G (9 m)}{r_{2}} \end{array}$

$V = - \frac{G m}{r_{1}} - \frac{G (9 m)}{r_{2}}$

$= - \frac{4G m}{r} - 12 \frac{G m}{r} = - \frac{16 G m}{r}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2020

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