Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationKepler's LawEasy2 minPYQ_2020

PhysicsEasysingle choice

A geostationary satellite is orbiting the Earth at a height of $6 R$ above the surface of the earth, $R$ being the radius of the Earth. The time period of another satellite, at a height of $2.5 R$ from the surface of the Earth, is

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Answer:

Solution:

A geostationary satellite has a time period of $T = 24 h r$ . From Kepler's law,

$T^{2} \propto R^{3} \Rightarrow \frac{T_{2}^{2}}{T_{1}^{2}} = \frac{R_{2}^{3}}{R_{1}^{3}} \Rightarrow \frac{T_{2}^{2}}{{(24)}^{2}} = \frac{{(R + 2.5 R)}^{3}}{{(R + 6 R)}^{3}}$

$T_{2} = \sqrt{\frac{24 \times 24}{8}} = 6 \sqrt{2} h r$ .

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Kepler's Law

⏱ 2mℹ️ Source: PYQ_2020

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