Start Free Mock LoginAlready registered? Login here

Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationSatellite MotionEasy2 minPYQ_2020

PhysicsEasysingle choice

Two particles of same mass $m$ go around a circle of radius $R$ under the action of their mutual gravitational attraction. The speed of each particle is ;

Options:

Answer:

Solution:

the gravitational force provide the necessary centripetal force for circular motion. so

$f_{g} = f_{e} \Rightarrow \frac{G m^{2}}{{(2 R)}^{2}} = \frac{m v^{2}}{R} \Rightarrow v = \frac{1}{2} \sqrt{(\frac{G m}{R})}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Satellite Motion

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...