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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2020

PhysicsEasysingle choice

A planet in a distant solar system is $10$ times more massive than the earth and its radius is $10$ times smaller. Given that the escape velocity from the earth is $11 km s^{- 1}$ , the escape velocity from the surface of the planet would be

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Answer:

Solution:

$v_{escape} = \sqrt{\frac{2 GM}{R}}$ for the earth

$v_{e} = 11 km s^{- 1}$

Mass of the planet = $10 M_{e}$ .

Radius of the planet = $\frac{R}{10}$ .

$∴$ $v_{e} = \sqrt{\frac{2 GM \times 10}{R / 10}} = 10 \times 11 = 110 km s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2020

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