Start Free Mock LoginAlready registered? Login here

Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationKepler's LawEasy2 minPYQ_2020

PhysicsEasysingle choice

A satellite which is geostationary in a particular orbit is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is :

Options:

Answer:

Solution:

$T^{2} \propto r^{3}$

$\frac{T_{1}}{T_{2}} = {(\frac{r_{1}}{r_{2}})}^{3 / 2}; \frac{24 h}{T} = {(\frac{r}{2 r})}^{3 / 2}$

$T = 24 (2 \sqrt{2}); T = 48 \sqrt{2} h$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Kepler's Law

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...