Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationField & ForceEasy2 minPYQ_2020

PhysicsEasysingle choice

Two point masses $M$ are kept fixed on the $x$ -axis at a distance $a$ from the origin, another point mass $m$ is moving in a circular path of radius $R$ (in $y - z$ plane) under the influence of gravitational force of attraction, then speed of $m$ will be
(Assume no forces are acting on $m$ other than the gravitational forces by two $M$ )

Options:

Answer:

Solution:

$F_{R} = 2 F \sin θ$
$\frac{m v^{2}}{R} = (2) (\frac{G M m}{r^{2}}) (\frac{R}{r})$
$r = \sqrt{a^{2} + R^{2}}$
$\Rightarrow v = \sqrt{\frac{2 G M R^{2}}{{(R^{2} + a^{2})}^{\frac{3}{2}}}}$

Subject:PhysicsTopic:GravitationSubtopic:Field & Force

⏱ 2mℹ️ Source: PYQ_2020

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