Physics - Gravitation Question with Solution | TestHub

The weight of an object at the surface of the earth is

$W=mg=m\frac{GM}{R^2}$

At a height $h=\frac{R}{2}$, the weight would be

$W^{\text{'}}=m\frac{GM}{{\left(R+h\right)}^2}=\frac{4}{9}\times m\frac{GM}{R^2}$

$\therefore W^{\text{'}}=\frac{4}{9}W$