Physics - Gravitation Question with Solution | TestHub

Given,

Depth$\left(d\right)=1600\mathrm{ k}\mathrm{m}$

We know that,

$g_d=g\left(1-\frac{d}{R}\right)$

Here,$g=9.8\mathrm{ m} {\mathrm{s}}^{-2}$

$R=6400\mathrm{ k}\mathrm{m}$

$g_d=g\left(1-\frac{1600}{6400}\right)$

$=9.8\left(1-\frac{1}{4}\right)$

$=9.8\left(\frac{4-1}{4}\right)=\frac{9.8\times 3}{4}$

$g_d=7.35\mathrm{ m} {\mathrm{s}}^{-2}$