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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationKepler's LawEasy2 minPYQ_2020

PhysicsEasysingle choice

The time period of a satellite of earth is $5$ hours. If the separation between the earth and the satellite is increased to $4$ times the previous value, the new time period will become

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Answer:

Solution:

According to Kepler's law $T^{2} \propto r^{3}$

$∴$ ${(\frac{T_{1}}{T_{2}})}^{2} = {(\frac{r_{1}}{r_{2}})}^{3} = {(\frac{1}{4})}^{3} = \frac{1}{64}$ or $\frac{T_{1}}{T_{2}} = \frac{1}{8}$

or $T_{2} = 8 T_{1} = 8 \times 5 = 40 hrs$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Kepler's Law

⏱ 2mℹ️ Source: PYQ_2020

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