Physics - Gravitation Question with Solution | TestHub

At equator

$\mathrm{g}\text{'}=\mathrm{g}-{\mathrm{\omega }}^2\mathrm{R}$

When earth suddenly stops$\mathrm{\omega }=0$

$\mathrm{g}\text{'}=\mathrm{g}-{\left(0\right)}^2\mathrm{R}$

$\mathrm{g}\text{'}=\mathrm{g}$

This mean$\mathrm{g}$will increase.