What is the binding energy of earth-sun system neglecting the effect of other planets and satellites? (Mass of earth M e = 6 × 10 24 k g , mass of the sun M s = 2 × 10 30 k g - 2 , Distance between earth & sum = 1.5 × 10 11 m ) Assume circular orbit of earth around sun

Binding energy of the system = - G M e M s 2 r = - 6.6 × 10 - 11 × 6 × 10 24 × 2 × 10 30 2 × 1.5 × 10 11 = - 2.6 × 10 33 J B E = 2.6 × 10 33 J

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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationSatellite MotionEasy2 minPYQ_2020

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What is the binding energy of earth-sun system neglecting the effect of other planets and satellites? (Mass of earth $M_{e} = 6 \times 10^{24}$ $k g,$ mass of the sun $M_{s} = 2 \times 10^{30} k g^{- 2},$ Distance between earth & sum $= 1.5 \times 10^{11} m$ ) Assume circular orbit of earth around sun

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Answer:

Solution:

Binding energy of the system $= \frac{- G M_{e} M_{s}}{2 r}$

$= \frac{- 6.6 \times 10^{- 11} \times 6 \times 10^{24} \times 2 \times 10^{30}}{2 \times 1.5 \times 10^{11}}$

$= - 2.6 \times 10^{33} J$

$|B E| = 2.6 \times 10^{33} J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Satellite Motion

⏱ 2mℹ️ Source: PYQ_2020

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