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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle is projected with velocity $k v_{e}$ in vertically upward direction from the ground into the space ( $v_{e}$ is escape velocity & $k < 1$ ) then the maximum height from the centre of earth to which it can go, will be

Options:

Answer:

Solution:

Total energy of surface = Total energy at $h$ height

$\Rightarrow \frac{1}{2} m {(k v_{e})}^{2} + \{\frac{- G M m}{R}\} = U + \{\frac{- G M m}{R + h}\}$

$\Rightarrow h = \frac{R k^{2}}{1 - k^{2}}$

From the centre

$r = R + h = \frac{R}{1 - k^{2}}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2020

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