Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationSatellite MotionEasy2 minPYQ_2020

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An artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of escape velocity from the earth. The height of satellite above the surface of earth is -(where $R = r a d i u s o f e a r t h$ )

Options:

Answer:

Solution:

escape velocity $V_{s} = \sqrt{\frac{2 G m}{R}}$

orbital velocity $V_{0} = \sqrt{\frac{G m}{r}}$

given $V_{0} = \frac{1}{2} V_{e}$

⇒ $\sqrt{\frac{G m}{R + h}}$ $= \frac{1}{2} \sqrt{\frac{2 G m}{R}}$

$\Rightarrow R + h = 2 R$ or $h = R$

Subject:PhysicsTopic:GravitationSubtopic:Satellite Motion

⏱ 2mℹ️ Source: PYQ_2020

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