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PhysicsGravitationField & ForceMedium2 minPYQ_2019
PhysicsMediumsingle choice

The value of acceleration due to gravity at Earth's surface is 9.8 m s-2. The altitude above its surface at which the acceleration due to gravity decreases to 4.9 m s-2, is close to: (Radius of earth =6.4×106 m)

Options:

Answer:
B
Solution:

Acceleration due to gravityg=GMR2.......(1)
g2=GM(R+h)2............(2)
From (1) and (2),
GM2R2=GM(R+h)2
R+h=2R
h=0.414×6.4×106
=2.6×106 m

Stream:JEESubject:PhysicsTopic:GravitationSubtopic:Field & Force
2mℹ️ Source: PYQ_2019

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