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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialMedium2 minPYQ_2019

PhysicsMediumsingle choice

The kinetic energy of a revolving satellite $(m a s s m)$ at a height equal to thrice the radius of the earth $(R)$ is

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Answer:

Solution:

$K \cdot E . = \frac{G M m}{2 (R + h)}$
$K \cdot E . = \frac{G M m}{2 (R + 3 R)} = \frac{G M m}{8 R} \times \frac{R}{R} = \frac{1 m .}{8} (\frac{G M m}{R^{2}}) \cdot R$
$K \cdot E . = \frac{m g R}{8} (∵ \frac{G M}{R^{2}} = g)$

Stream:MHT_CETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2019

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