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Physics - Gravitation Question with Solution | TestHub

PhysicsGravitationEnergy & PotentialEasy2 minPYQ_2016

PhysicsEasysingle choice

The ratio of escape velocity at earth $(υ_{e})$ to the escape velocity at a planet $(υ_{p})$ whose radius and mean density are twice as that of earth is:

Options:

Answer:

Solution:

$\frac{v_{e}}{v_{P}} = \frac{\sqrt{2 \frac{G M_{e}}{R_{e}}}}{\sqrt{2 \frac{G M_{P}}{R_{P}}}} = \sqrt{\frac{M_{e} R_{P}}{M_{P} R_{e}}} = \sqrt{\frac{ρ_{e} \frac{4}{3} π R_{e}^{3} R_{P}}{ρ_{p} \frac{4}{3} π R_{P}^{3} R_{e}}}$

$\frac{v_{e}}{v_{P}} = \sqrt{\frac{ρ_{e} R_{e}^{2}}{ρ_{p} R_{P}^{2}}} = \sqrt{\frac{1}{2 \times 2^{2}}} = \frac{1}{2 \sqrt{2}}$

Stream:NEETSubject:PhysicsTopic:GravitationSubtopic:Energy & Potential

⏱ 2mℹ️ Source: PYQ_2016

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